starzboy Posted April 21, 2006 Share Posted April 21, 2006 find the correct pass for the crackme !no brute forcing is allowed !http://d.turboupload.com/d/533559/crackme_0.rar.htmlPS : Please do not post you answer here [only one pass] let others try their luck too !Thankyou Link to comment Share on other sites More sharing options...
yamraaj Posted April 22, 2006 Share Posted April 22, 2006 (edited) It was easier then what i thought You know binary Edited April 22, 2006 by yamraaj Link to comment Share on other sites More sharing options...
starzboy Posted April 23, 2006 Author Share Posted April 23, 2006 good !and why do you ask .... ? ! Link to comment Share on other sites More sharing options...
Hybr!d Posted April 23, 2006 Share Posted April 23, 2006 This doesnt look so easy for me. These are my steps.1) Opened in Peid looked for any sort of packaging.2) Opened in Olly then ran the program to get background information.3) I searched for all referenced strings and found the part where it says Access Granted and so on.4) I follow in dissassembler then I am lost because I see nothing. All I see is a bunch of CALLS and MOV's and JMP's nothing else.Help would be appreciated as I am trying to learn as I go. Link to comment Share on other sites More sharing options...
The Old Pirate Posted April 23, 2006 Share Posted April 23, 2006 @Hybr!d, tip: look at some constant just above string "CRACKME FOR NEWBIE #0 !" Link to comment Share on other sites More sharing options...
yamraaj Posted April 23, 2006 Share Posted April 23, 2006 good !and why do you ask .... ? ! Sorry....that was just a lame tip Link to comment Share on other sites More sharing options...
Guest Tundra Posted April 23, 2006 Share Posted April 23, 2006 Hybr1d - You know there are two possible outcomes after you type in the serial. Either you get the "Access Granted!" message or you get the "Access Denied!" one. So, at one point in the program, there has to be some kind of conditional jump to decide which one to go to, and the most common way to create a conditional jump is to have CMP x, yJNZ (or JZ) addressLook around in the code for this...Hope this helps Link to comment Share on other sites More sharing options...
ALiEN Posted April 23, 2006 Share Posted April 23, 2006 It was easier then what i thought You know binary Yeh, it's the way to solution... ALiEN. Link to comment Share on other sites More sharing options...
Hybr!d Posted April 23, 2006 Share Posted April 23, 2006 Thanks for the Tips guys I got it . The answer was right in front of me...Should of looked at the CMP and followed it through. Link to comment Share on other sites More sharing options...
starzboy Posted April 24, 2006 Author Share Posted April 24, 2006 i hope all of you like this crackme !I AM LEARNING C++ AND WILL SOON BE MAKING MORE !Regards starzboy ! Link to comment Share on other sites More sharing options...
Hybr!d Posted April 26, 2006 Share Posted April 26, 2006 Make more indeed... Make it abit harder next time for people like me Link to comment Share on other sites More sharing options...
starzboy Posted April 26, 2006 Author Share Posted April 26, 2006 Make more indeed... Make it abit harder next time for people like me i am still learning and yes....ill try my best to make it harder ! Regards starzboy! Link to comment Share on other sites More sharing options...
futureproof Posted April 30, 2006 Share Posted April 30, 2006 It was quite easy...Solved Link to comment Share on other sites More sharing options...
Guest Findme Posted May 31, 2006 Share Posted May 31, 2006 hmm im having trouble with this. i guess i need more tutorials ... Link to comment Share on other sites More sharing options...
Guest linkin Posted June 3, 2006 Share Posted June 3, 2006 hmm im having trouble with this. i guess i need more tutorials ... me, too... I know, that there is something in this Call: 0040146C ... but, I can't find the real password. I know, that I can only use numbers for the password. I think, starzboy has converted the number to HEX (my entered number, too) ... an checked them . I'm trying (Nice Crackme starzboy, I love it ) Link to comment Share on other sites More sharing options...
starzboy Posted June 6, 2006 Author Share Posted June 6, 2006 hmmm....this is how "Giga"....explains !0040145D |. C74424 04 01000>MOV DWORD PTR SS:[ESP+4],100401465 |. C70424 60344400 MOV DWORD PTR SS:[ESP],crackme_.004434600040146C |. E8 0F540200 CALL crackme_.0042688000401471 |. 8B45 F8 MOV EAX,DWORD PTR SS:[EBP-8] ; kernel32.7C816D5800401474 |. 3B45 FC CMP EAX,DWORD PTR SS:[EBP-4] <-------------------------------------------BP00401477 |. 75 3A JNZ SHORT crackme_.004014B300401479 |. C74424 04 44004>MOV DWORD PTR SS:[ESP+4],crackme_.004400>; ASCII "Access Granted !"00401481 |. C70424 C0334400 MOV DWORD PTR SS:[ESP],crackme_.004433C000401488 |. E8 E7AC0300 CALL crackme_.0043C1740040148D |. C74424 04 44AF4>MOV DWORD PTR SS:[ESP+4],crackme_.0043AF>00401495 |. 890424 MOV DWORD PTR SS:[ESP],EAX00401498 |. E8 238C0200 CALL crackme_.0042A0C00040149D |. C74424 04 55004>MOV DWORD PTR SS:[ESP+4],crackme_.004400>; ASCII "WELCOME !"004014A5 |. C70424 C0334400 MOV DWORD PTR SS:[ESP],crackme_.004433C0004014AC |. E8 C3AC0300 CALL crackme_.0043C174004014B1 |. EB 38 JMP SHORT crackme_.004014EBand we will have something like this:Stack SS:[0022FF74]=3C34EB12 <----------- Serial in hex formatEAX=00000037and when convert this to Decimal the result is 1010101010serial = 1010101010 Link to comment Share on other sites More sharing options...
SunBeam Posted June 21, 2006 Share Posted June 21, 2006 Yup, so true. Different from anything else, is the fact that C++ applications make use of the stack in 95% of the cases No wonder people couldn't find any traces of clues just by looking at the strings Works fast with Olly scripting Link to comment Share on other sites More sharing options...
Guest slavaa Posted July 2, 2006 Share Posted July 2, 2006 it was kind of hard for me cause im a bit of a noob ey nice job tho, i found out eventually after a while Link to comment Share on other sites More sharing options...
starzboy Posted July 2, 2006 Author Share Posted July 2, 2006 i recomend that when you are going thro' a C++ app...you should know the details you entered in Hex so that whe you spot the info in hex you will kjnow that you are somewhere close !Justa Tip....thats what i do ! Link to comment Share on other sites More sharing options...
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