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[Keygenme] XorRanger's KeygenMe 4


XorRanger

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Hello All,

It's been a While Since I Posted Any Challenge
This Should Be Quite Easy But I Will Let You all Decide
Solution: Only Keygens Are Allowed.
A Tutorial Would Be An Added Bonus.
Language: Delphi
Packer: UPX. Simply Use "upx -d " to Decompress 
Please Solve. Thanks

 

XorRanger KeygenMe #4.zip

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Damn! Too easy my friend :)

name: BREAD 'n' BUTTER
serial: A17B-2C43-49D5-*DAER

A combo for now but will make a tut soon.

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Damn, Now am Scared Of You.
I Thought This Would be Some Challenge For You But You Proved Me Wrong. :pinch:
You Never Cease to Amaze Me and Must Confess That You Inspire Me.

Well Done Master ChOoKi.  :plane:

 

** By the Way, How Did You Get The 3 Combo Chars Cos I See You Got 2 Different Valid Combinations Of  Combos. (By Brute Forcing or Calculation) ?

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many thank for this little challange


 


Keep up the spirit.



.data
Base db "0123456789ABCDEF",0 .data?
szName db 60 dup(?)
szKey db 60 dup(?) .code
Gen proc uses edi esi ebx hWnd:HWND invoke GetDlgItemText, hWnd, IDC_NAME, addr szName, SizeOf szName .if eax >= 5
xor ebx,ebx
xor ecx,ecx
lea edi,szKey
xor edx,edx .while ebx < 15
.if ebx == 4 || ebx == 9 || ebx == 14
mov byte ptr[edi], 2Dh
inc edi
.else
call RndCharacter
mov edx,eax
movzx edx, byte ptr[Base][edx]
invoke wsprintf,addr szKey,CTEXT("%s%C"), addr szKey,edx
inc edi
.endif
inc ebx
.endw
mov byte ptr[edi],'*'
mov byte ptr[szKey][2],'7'
mov byte ptr[szKey][7],'5'
mov byte ptr[szKey][11],'0' inc edi
lea esi, szName
mov ecx,4
.while ecx
mov dl, byte ptr[esi][ecx]
mov byte ptr[edi],dl
inc edi
dec ecx
.endw
.else
invoke SetDlgItemText, hWnd, IDC_KEY, CTEXT("Name! ?")
ret
.endif
invoke SetDlgItemText, hWnd, IDC_KEY, addr szKey
ret
Gen endp
RndCharacter Proc uses ecx edx rdtsc
mov ecx,41c64e6dh
mul ecx
add eax,3039h
and eax,7ffffffh
mov ecx, 26
sub edx,edx
div ecx
xchg eax,edx
and eax, 0Fh ret
RndCharacter EndP

Sol_XorRanger_4.rar

Edited by sama
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many thank for this little challange

 

Keep up the spirit.

.data

Base db "0123456789ABCDEF",0

.data?

szName db 60 dup(?)

szKey db 60 dup(?)

.code

Gen proc uses edi esi ebx hWnd:HWND

invoke GetDlgItemText, hWnd, IDC_NAME, addr szName, SizeOf szName

.if eax >= 5

xor ebx,ebx

xor ecx,ecx

lea edi,szKey

xor edx,edx

.while ebx < 15

.if ebx == 4 || ebx == 9 || ebx == 14

mov byte ptr[edi], 2Dh

inc edi

.else

call RndCharacter

mov edx,eax

movzx edx, byte ptr[Base][edx]

invoke wsprintf,addr szKey,CTEXT("%s%C"), addr szKey,edx

inc edi

.endif

inc ebx

.endw

mov byte ptr[edi],'*'

mov byte ptr[szKey][2],'7'

mov byte ptr[szKey][7],'5'

mov byte ptr[szKey][11],'0'

inc edi

lea esi, szName

mov ecx,4

.while ecx

mov dl, byte ptr[esi][ecx]

mov byte ptr[edi],dl

inc edi

dec ecx

.endw

.else

invoke SetDlgItemText, hWnd, IDC_KEY, CTEXT("Name! ?")

ret

.endif

invoke SetDlgItemText, hWnd, IDC_KEY, addr szKey

ret

Gen endp

RndCharacter Proc uses ecx edx

rdtsc

mov ecx,41c64e6dh

mul ecx

add eax,3039h

and eax,7ffffffh

mov ecx, 26

sub edx,edx

div ecx

xchg eax,edx

and eax, 0Fh

ret

RndCharacter EndP

 

@Sama, Thanks For Solving.

Edited by XorRanger
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char User[20];

char Serial[20];

static const char alphanum[] =

"0123456789";

int stringLength = sizeof(alphanum) - 1;

 

void main(){

srand(time(0));

printf("Username:\n");

scanf("%s",User);

if(strlen(User)<5){

ExitProcess(0);

}

int value = 0 ;

BOOL FD = FALSE;

 

for(int k = 0; k <= 15; k ++){

for(int i = 1 ; i <= 15 ; i++){

for(int j = 2; j <=15;j++){

if(!FD){

__asm{

//Brute-force

MOVZX EAX,k

MOVZX ECX,i

MOVZX EDX,j

MOV ESI,ECX

MOV EBX,0x0B92C3

MOV ECX,EDX

MOV EDX,EAX

SHL EDX,CL

XOR ESI,EAX

IMUL EDX,ESI

XOR EBX,EDX

MOV value,EBX

}

printf("Hex : %X \n" , value);

printf("Int :%i \n",value);

if(value == 759011){

printf("Values : \n%i\n%i\n%i\n" , k,i,j);

FD = TRUE;

}

}

}

}

}

char lastChars[5];

for(int o = 0 ; o < 4; o++){

 lastChars[o] = User[o+1];

}

lastChars[4] = '*';

 

printf("%s\n",lastChars);

for(int i = 0 ; i < 20 ; i++){

Serial  = alphanum[rand() % stringLength];

}

Serial[2] = '7';

Serial[11] = '9';

Serial[7] = '4';

 

Serial[4] = '-';

Serial[9] ='-';

Serial[14] = '-';

 

int count  = 4 ;

for(int k = 15 ; k <20 ; k++){

Serial[k] = lastChars[count];

count --;

}

printf("\nSerial Generated for username : \n%s\n" , Serial);

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char User[20];

char Serial[20];

static const char alphanum[] =

"0123456789";

int stringLength = sizeof(alphanum) - 1;

 

void main(){

srand(time(0));

printf("Username:\n");

scanf("%s",User);

if(strlen(User)<5){

ExitProcess(0);

}

int value = 0 ;

BOOL FD = FALSE;

 

for(int k = 0; k <= 15; k ++){

for(int i = 1 ; i <= 15 ; i++){

for(int j = 2; j <=15;j++){

if(!FD){

__asm{

//Brute-force

MOVZX EAX,k

MOVZX ECX,i

MOVZX EDX,j

MOV ESI,ECX

MOV EBX,0x0B92C3

MOV ECX,EDX

MOV EDX,EAX

SHL EDX,CL

XOR ESI,EAX

IMUL EDX,ESI

XOR EBX,EDX

MOV value,EBX

}

printf("Hex : %X \n" , value);

printf("Int :%i \n",value);

if(value == 759011){

printf("Values : \n%i\n%i\n%i\n" , k,i,j);

FD = TRUE;

}

}

}

}

}

char lastChars[5];

for(int o = 0 ; o < 4; o++){

 lastChars[o] = User[o+1];

}

lastChars[4] = '*';

 

printf("%s\n",lastChars);

for(int i = 0 ; i < 20 ; i++){

Serial  = alphanum[rand() % stringLength];

}

Serial[2] = '7';

Serial[11] = '9';

Serial[7] = '4';

 

Serial[4] = '-';

Serial[9] ='-';

Serial[14] = '-';

 

int count  = 4 ;

for(int k = 15 ; k <20 ; k++){

Serial[k] = lastChars[count];

count --;

}

printf("\nSerial Generated for username : \n%s\n" , Serial);

@WormFC, Thanks For Solving.

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Hey.


Sorry to be late.


Here is one from me.


:)



Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
If TextBox1.Text.Length < 5 Then
Return
End If Dim rand As New Random
Dim letter As String = ""
For i = 0 To 20
letter = letter & ChrW(rand.Next(Asc("A"), Asc("Z") + 1))
Next
Dim invers As String = "*" & StrReverse(TextBox1.Text.Substring(1, 4))
Dim p1 As String = letter.Substring(0, 2) + "7" + letter.Substring(2, 1)
Dim p2 As String = letter.Substring(3, 2) + "4" + letter.Substring(5, 1)
Dim p3 As String = letter.Substring(6, 1) + "9" + letter.Substring(8, 2)
TextBox2.Text = p1 + "-" + p2 + "-" + p3 + "-" + invers
Clipboard.SetText(TextBox2.Text.Trim)
End Sub Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
TextBox1.Text = Environment.UserName
End Sub
End Class


 


Name: forum.tuts4you.com


Serial:  =D7W-GF4:-;9;<-*muro


Keygen.7z

Edited by GIV
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