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Error generating a random letter in VB.NET


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Hope someone can give me a hint, because I have the following code copied from reflector(VB.NET) into vb express edition 2010, but I have a lot of errors, so I started fixing the code, but i ended with an error, which it seems I , not yet, can't resolve myself. Here she comes:

Private Function genRandomLetter(ByVal rand As Random) As CharReturn IIf((rand.Next(1, 3) = 1), DirectCast(rand.Next(&H41, 90), Char), DirectCast(rand.Next(&H61, &H7A), Char)))End Function

And here is the error:

Error 2 'Integer' values cannot be converted to 'Char'. Use 'Microsoft.VisualBasic.ChrW' to interpret a numeric value as a Unicode character or first convert it to 'String' to produce a digit.

This solution offered seems to be impossible, only error after error.

So, I tried to declare "Char" as string, as Integer and as Object, but unfortunately, "Char" can't be used.

So I used "x" or whatever,instead of "Char" as char/string/integer, no good again.

This solution doesn't work for me at all!

Here are the Imports I included:

Imports System.Reflection
Imports System.Reflection.Emit
Imports System.Windows.Forms
Imports System.Security.Cryptography
Imports System.Text
Imports System.ComponentModel
Imports System.Globalization
Imports System.Threading
Imports System.Windows
Imports Microsoft.VisualBasic.CompilerServices

That's about it, any tips are welcome.



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    Public Function GenerateRS(ByVal Length As Int32) As String        Dim Base As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"        Dim Chars() As Char = Base.ToCharArray        Dim FinalString As New System.Text.StringBuilder(Length)        Dim RN As New Random(Now.Millisecond)        For i As Int32 = 1 To Length            FinalString.Append(Chars(RN.Next(0, Chars.Length - 1)))        Next        Return FinalString.ToString    End Function
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Thanks for the code Kurapica,

I made my own solution with someones else help, here she comes:

Private Function genRandomLetter(ByVal rand As Random) As Char Return IIf((rand.Next(1, 3) = 1), Convert.ToChar(rand.Next(&H41, 90)), Convert.ToChar(rand.Next(&H61, &H7A))) End Function

Also convert Integer to Char, whithout any probs.

Have a nice day and thanks for your time.

Edited by grizzmo
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