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Leaderboard

  1. lovejoy226

    lovejoy226

    Full Member+
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    1,433
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  2. CodeExplorer

    CodeExplorer

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    4,492
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  3. zaas

    zaas

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  4. blackpirate

    blackpirate

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Popular Content

Showing content with the highest reputation since 12/18/2025 in Posts

  1. CodeExplorer
    Here is unpacked folder, all tools included. https://limewire.com/d/PWsfv#C32mVemS40 https://fileroy.com/2WVGr1E9zkx7/file https://zippyshare.day/YPGm89uDHMSpeoC/file Final unpacked exe is called drr_msil_Slayed2cleaned_.exe
  2. Washi
    3 points
    Better late than never, my writeups are finally live: https://washi1337.github.io/ctf-writeups/writeups/flare-on/2025/
  3. CodeExplorer
    NETReactorSlayer-6.4.0.0_Fixed9.rar: https://workupload.com/file/9FgKGVGdEEY I completely restored NETReactorSlayer-6.4.0.0\NETReactorSlayer.Core\Helper\EncryptedResource.cs and just add trial Decrypter_v5. I've added ControlFlowReactor.cs for the new control flow and I've changed MethodDecrypter.cs to call it from "public void Run(IContext context)" in each Module.cctor method called.
  4. CodeExplorer
    I've just fixed NETReactorSlayer to work with this protection: NETReactorSlayer-6.4.0.0_Fixed1: https://workupload.com/file/EU2AEkDCjSz Please test it and let me know;
  5. CodeExplorer
    https://limewire.com/d/ms51G#Mpzupr348q https://fileroy.com/M2BGwO2XGj40/file https://zippyshare.day/EbxBhxDZZZbrlIH/file
  6. 0xFFFFDAY
    you really want then open a new challenge of unpack me. Will try to do it. Like a proper way.
  7. 0xFFFFDAY
    Ok will prove it what will i get?
  8. Asif
    its not trial , its dng hvm enterprise 4.94 [ it can be run for 3 days ] , unpack it here x86 and x64 bit , Unpackme_64bit_3_days_time.zip UnpackMe_3_Days.zip
  9. Asif
    i am not asking about how did u dump jit code , saying about , can u little bit brief about => how did you Load assembly and RunModuleConstructor or load assembly from different Domain, this part => var asm = Assembly.LoadFrom(Filename); RuntimeHelpers.RunModuleConstructor(asm .ManifestModule.ModuleHandle);
  10. decode
    @CodeExplorer Hello master, I followed your instructions for the new version of this application, but the code doesn't fully open and the executable still doesn't work. Could you please review it again? Your knowledge regarding this version of Reactor is very valuable to me. https://gofile.io/d/c1jG6d
  11. Nooboy
    <font dir="auto" style="vertical-align: inherit;"><font dir="auto" style="vertical-align: inherit;">SEKeygen.rar</font></font>HWID hash: 83A5249484F096DB700F771CF0A5F51B Decoded value 8A357B71C2ECFA5F7FC3275B5DBF9F61D4F98CA089470FCF390DFC0BC125917C92D667ACA678A0D485F7566FBBA52233 Reg SOFTWARE\Classes\Interface\{19335D77-1E2D-1337-146B-19F5CABF57A8} KeySize: 1024 E: 65537 CPU MAC BIOS HDD HWID
  12. iced
    Very nice crackme Salin! Noticed couple of things and gave it a try,its using a recrusive function that looked like Fbonacci but with a twist - when n equals 8 it returns the first character of my input XORed with 0x78 instead of the normal Fibonacci value. Code computes fib(14) and compares it against specific values in a switch statement. I knew standard fib(14) is 377 which equals 0x179. Working backwards since fib(8) gets replaced with char[0] ^ 0x78 , i needed to figure out what value makes the sequance land on 377. Turns out fib(8) needs to be 21 for this to work. So char[0] ^ 0x78 = 21 which means char[0] = 21 ^ 0x78 = 0x6D = 'm' There's a loop that validates characters 3 through 9 using a table at byte_411BFC. The validation formula : fib(i+8) - fib(i+6) == byte_411BFC[i] ^ char[3+i] Just rearranged it to solve for each character and u get : a, m, b, i, q, u, e. Now characters 1 and 2 were trickier. Character 1 determines a value dl through another Fibonacci call and character 2 gets XORed with that. There's a secondary check involving fib(17) that needs to equal 1597. After some trial and error found that char[1] = 'o' gives the right Fibonacci value, and char[2] = 'z' satisfies the XOR constraint. And if we finally put it all together we get a valid serial for this amazing crackme which is : mozambique I ran it through checksum calculation and got 0x12D4. Some code where it compares : 0040134B | 893D 20434100 | mov dword ptr ds:[414320],edi | 00401351 | 81FF D4120000 | cmp edi,12D4 |
  13. lovejoy226
    The Enigma Protector x64 v7.4 (HWID Lock) Two simple Win x64 GUI applications protected using Enigma x64 v7.4. Challenge is to; bypass the hardware ID lock; unpack the application. Let us go together to solve this issue. File Information Submitter lovejoy226 Submitted 06/17/2024 Category UnPackMe View File
  14. lovejoy226
    @everyone Can you please write step by step guide tutorials if you solve these kind of problems, so other people get helped by your efforts. No meaning jobs, just showing off. But this is not obligation. your choice for helping others learn. Regards. sean.
  15. Priboi

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