hello tuts4you, i got a simple math question.

 

when a lenght of a string divisible by 36, the counter should be added by 10.So i got this working but i bet there is a better/cleaner way to do this.

 

 

this is what i got and it works, but could someone help me to improve my function?

invoke lstrlen, Addr szString

.if eax <= 36

     push 10

.elseif eax <= 72  ; + 36

     push 20	   ; + 10

.elseif eax <= 108 ; + 36

     push 30       ; + 10 etc..

.elseif eax<= 144

     push 40

.elseif eax <= 180

     push 50

.elseif eax <= 216

     push 60

.elseif eax <= 252

     push 70

.else	

     push 80

.endif

Modulo operation

 

ASM DIV look EDX == 0?

// -- divide length by 36, add one

CDQ

MOV ECX,24h

DIV ECX

INC EAX

// -- if result is more than 8, set it to 8

CMP EAX,8

JBE @F

MOV EAX,8

@@:

// -- multiply result by 10, in EAX will be the value we need

MOV ECX,0Ah

MUL ECX

again tuts4you helped me out, a LOT of thanks kao and Aguila, problem solved