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Tuts 4 You

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Featured Replies

Hehe your know the last brocken key? :prop:


 


Good luck with your solution


@Nooby



I'm trying my best to follow your path :smilie3: .


 


Thanks!


  • Author

@MistHill
Off topic: I'll factor that 512bit modulus, so you don't need to patch it.:)

Actually I'v re-read the Miller's Theory, and in deed not only this exploit is very antique it is also the basis of the most primality tests. I wasn't aware of this at all.


 


User: Tuts4You


Req: A799CB8D37C11F8052AA59674A0E89957205F69BE447F887306A02934F4863652C418D6B268070B4B95C500B89FD89D13612D0A9961E0FA39CD033A094F015B5E0FB48BFA37D25834496AD4D68E4FA097D0454303545C89CCBD9898D96021CA8480F06414D8BD28A194C5786EA167BACBD19E259E803EBBB6C74D7367E4615873FD8CA2654055E564DFA145C1A62FAC9DE5D156709F6B6067B014C9DF4D7C7A32E7012B84859AF9A3232EF531904045F272ABBE063D75336B516226049BEAD28


 


Act: your key is: 1e10de218320d31489c3b293ea4837dd90c0b12ae27c341fcd4a41f364b03892cd6048496a8161012c356a9a22f56d74e8fd7a64f59ebe01fbeba3371d1fed8a


 


I also need to reprogram my rng attack, (this one is taking about 5 minutes do generate a key)


kg.zip

  • Author

Great work. Looking forward to your optimized RNG attack. Step 1 is inspired by DSA-1571-1 which lead to a major reissue of certificates across the Internet. Now you've learned some notable properties of RSA, I'm glad that my KeygenMe served its purpose.


  • Solution

Essentially what I had, but now it is trully O(2^16) via a table.


KeygenMe.zip

  • Author

Solution accepted. One slight improvement to make it O(1): multiply all primes from the table, calculate gcd(primes, N) to find out witch. :)

@MistHill

Off topic: I'll factor that 512bit modulus, so you don't need to patch it. :)

Hmily told me you've succeeded almost within one week!?

 

Essentially what I had, but now it is trully O(2^16) via a table.

Excellent work!

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