[CrackMe] CrackMe v1.1

[Greedy_Fly]

Hi All...

Test It!!!

 

Rules:

- Valid Serial + tutorial

- No bruteforce allowed!

 

CrackMe1.1.zip

 

Good Luck!!!

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Greedy Fly

 

 

[ChOoKi]

Serial : 181804461EDC771ED0FD0673

 

Is it the same one posted here? http://www.crackmes.de/users/greedy_fly/crackme_v1.1/

[sama]

0x8166F372 == 2171007858 dec

0x16F0599C == 384850332  dec

 

equations to solve to get a point of start  :2171007858 - 3x == y
4y - 3x == 384850332

 

where

y == value of the middel 8 digits

x == Value of first 8 digitswe transform the equations so that  variables are on the one side and on the other the valueso our equation become

 

- 3 * x - y == - 2171007858 (dont forget the sign) !
- 3 * x + 4 * y == 384850332By dividing the first Equation by -3 , we eliminate the factor before x :
            
 x + 1/3 * y == 723669286
              
- 3 * x + 4 * y == 384850332With the first Equation, which is in all other equation of the summand eliminated by x.For the second Equation, we add 3 times the 1 Equation :x + 1/3 * y == 7236692865 * y == 2555858190Dividing the second Equation by 5, the factor in front of y is eliminated :x + 1/3 * y == 723669286y == 511171638With the second Equation is eliminated in all other equation of the summand with y .To finish the first Equation we subtract y/3 from first equation

 

so that the result is:
 

x == 553278740 => 0x20FA5D14 y == 511171638 => 0x1E77DC36

 

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So, the rest of the crackme should be simple, in fact what remains is simple math

I dont want to spoil out the full solution, while with those infos should everyone be able to calculate the final key

 

And no bruteforcing is needed

 

sorry for my poor english i use a translator.

[simple]

[ChOoKi]

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Edited November 28, 2013 by ChOoKi