[KeyGenMe] .NET Keygen Me

[master131]

 

This is my first keygen-me so good luck.

 

Original Language: C#

Difficulty: Beginner to Intermediate

Obfuscated: Yes (SmartAssembly)

Self-Keygen/IL-Patching: No

 

Not sure if the algo I wrote is used in real software but it works and creating a keygen for it shouldn't be too difficult.

Keygen Me.rar

Edited July 15, 2013 by master131

[CodeExplorer]

So we have 5 groups separated by "-"
each group is a hex number! class0_0.int_0 is a int array:
 int[] numArray = new int[] { 5, 2, 4, 6, 7 };   string[] strArray;
    if (string.IsNullOrEmpty(string_0))
    {
        return false;
    }
    if ((strArray = string_0.Split(new char[] { '-' })).Length != class0_0.int_0.Length)
    {
        return false;
    }
    List<int> list = new List<int>();
    foreach (string str in strArray)
    {
        int num;
        if (str.Length != 4)
        {
            return false;
        }
        if (!int.TryParse(str, NumberStyles.HexNumber, null, out num))
        {
            return false;
        }
        list.Add(num);
    }in the end we have a list with numbers!
The most important part:
for (int i = 0; i < list.Count; i++)
    {
        int num3 = 0;
        foreach (char ch in Convert.ToString(list, 2))  // convert int to base 2
        {
            num3 += (ch == '1') ? 1 : 0;
            // here char can be only 1 or 0 since is base 2
            // when char is 1 add 1 to the number
        }
        if (num3 != class0_0.int_0)
        {
            return false;
        }
    }
    return true;So  int[] numArray = new int[] { 5, 2, 4, 6, 7 };
means numbers of "1" in binary!Still don't know how to generate serials yet!

[LordCoder]

@CodeCracker I think this keygenme it's imposible to solve because each group must be 4 like this:

 

xxxx-xxxx-xxxx-xxxx-xxxx

 

If we replace the x with 1 with be 4 +1:

 

1111-1111-1111-1111-1111

 

num3 then the maximum value can be 4. The array contains 5, 2, 4, 6, 7. So the only possible serials that can be generated will be the 2nd and 3rd group on the serial. If we put another number that converted to base 2 will be also 1 or 0 so it's imposible to generate a serial.

[CodeExplorer]

LordCoder: you are actually wrong!

First of all each number is on Hexadecimal!

5 means 5 binary with "1": 11111 -> 1F -> 001F (since is 4 chars long)

2 means 2 binary with "1": 11 -> 3 -> 0003

4 means 4 binary with "1": 15 -> F -> 000F

6 means 6 binary with "1": 63 -> 3F -> 003F

7 means 7 binary with 1 -> 007F

Valid serial: 001F-0003-000F-003F-007F

and product registered!

I still don't know how to make a program which generates multiple serials :-D

I just do them manually!

Edited July 15, 2013 by CodeCracker

[ewwink]

maybe create empty space of 0 then fill it with 1 until 5,2,4,6,7  then convert it to hex like this 1001001101-100000001-100010101-1001100100101-11001101101 => 024d-0101-0115-1325-066d

Edited July 15, 2013 by ewwink

[master131]

Great job guys. Creating a keygen is possible, but it might involve some bruteforcing.

 

Hint: 0x0000-0xFFFF

Edited July 16, 2013 by master131

[kao]

Umm, no. No bruteforce required, just some brain.

PoC Keygen + relevant source attached.

kg_master131_by_kao.zip

[master131]

Umm, no. No bruteforce required, just some brain.

PoC Keygen + relevant source attached.

 

Or you could do that, lol. Nice job.

[GIV]

I have some hard time with this.

Here is my solution.

 

Keygen for master131 KeyGenMe.rar

[LordCoder]

It looked an easy target Yeah I was confused at it. Now I see it's better to do a protection with maths than with some other encryptions

[GIV]

My sources:

Public Class frmKeygen
    Function ConvertBinToHex(ByVal a As String) As String

        If a = "" Then

            Return String.Empty

        Else

            Return Convert.ToString(Convert.ToInt32(a, 2), 16).ToUpper

        End If

    End Function
    Private Sub cmdGenereaza_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdGenereaza.Click
        Dim rnd As New Random()

        Dim lungime As Integer = 4
        Dim strdup As String = "11011"

        Dim strreplicat As String = "0100"

        Dim index As String = rnd.Next(0, strdup.Length)

        Dim strfinal As String = strdup.Insert(index, strreplicat)
        txtSerial1.Text = "000" + ConvertBinToHex(strfinal)

        txtSerial1.Text = Strings.Right(txtSerial1.Text, lungime)
        Dim strdup1 As String = "010"

        Dim index1 As String = rnd.Next(0, strdup1.Length)

        Dim strfinal1 As String = strdup1.Insert(index1, strreplicat)

        txtSerial2.Text = "000" + ConvertBinToHex(strfinal1)

        txtSerial2.Text = Strings.Right(txtSerial2.Text, lungime)
        Dim strdup2 As String = "10101"

        Dim index2 As String = rnd.Next(0, strdup2.Length)

        Dim strfinal2 As String = strdup2.Insert(index2, strreplicat)

        txtSerial3.Text = "000" + ConvertBinToHex(strfinal2)

        txtSerial3.Text = Strings.Right(txtSerial3.Text, lungime)
        Dim strdup3 As String = "101100101"

        Dim index3 As String = rnd.Next(0, strdup3.Length)

        Dim strfinal3 As String = strdup3.Insert(index3, strreplicat)

        txtSerial4.Text = "000" + ConvertBinToHex(strfinal3)

        txtSerial4.Text = Strings.Right(txtSerial4.Text, lungime)
        Dim strdup4 As String = "111010110"

        Dim index4 As String = rnd.Next(0, strdup4.Length)

        Dim strfinal4 As String = strdup4.Insert(index4, strreplicat)

        txtSerial5.Text = "000" + ConvertBinToHex(strfinal4)

        txtSerial5.Text = Strings.Right(txtSerial5.Text, lungime)
        Dim serialfinal As String = txtSerial1.Text & "-" & txtSerial2.Text & "-" & txtSerial3.Text & "-" & txtSerial4.Text & "-" & txtSerial5.Text

        serialfinal = serialfinal.ToUpper

        Clipboard.SetText(serialfinal)

    End Sub

End Class

 

And attached is a little aesthetic change to the keygen.

Keygen for master131 KeyGenMe.rar

Edited July 16, 2013 by GIV