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[keygenme] s3rh47 FPU KeygenMe


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Posted

Hi All This My 1. KeygenMe in Tut4You

Coded by Radasm ( special Thanx Ketil O. )

Do not uses Pack and Criypto.

There are some FPU code.

I will a Keygen or Serial for your Name !

I wish good luck ( Sorry Bad English )

If you take a Message "Tebrikler Basardiniz" Register Succes!

KeygenMe-7.zip

s3rh47

TCCT TEAM ( Turkish Code Cracker Team )

Posted

The [keygenme] tag has been added to your topic title.

Please remember to follow and adhere to the topic title format - thankyou!

[This is an automated reply]

Posted

Thanx for Keygens

Posted (edited)

@ deepzero, your keygen doesn't run on my pc, I have win732bit.

and can someone maybe tell how to deal with FPU code in a keygen, I couldn't even fish a serial within 1,5 hour.

Thanks,

grizzmo

Edited by grizzmo
Posted (edited)
@ deepzero, your keygen doesn't run on my pc, I have win732bit.

as i said, q&c...but what exactly doesnt work? :)

here`s an important part of the fpu code commented:

00401251          DBE3        FINIT                     ; initialese FPU
00401253 53 PUSH EBX ; psuh ebx to stack
00401254 DB0424 FILD DWORD PTR SS:[ESP] ; load 1st dword of stack to st0
00401257 68 DA070000 PUSH 7DA ; push 7da to stack
0040125C DA0C24 FIMUL DWORD PTR SS:[ESP] ; multiply st0 * 1st dword of stack, store result in st0
0040125F 6A 06 PUSH 6 ; psuh 6 to stack
00401261 DA3424 FIDIV DWORD PTR SS:[ESP] ; div st0 / 1st dword of stack, store result in st0

"translated" to "normal" asm:

        MOV EAX,0X7DA
MUL EBX
MOV EBX,6
DIV EBX

dp0 :)

Edited by deepzero
Posted (edited)

Thanx for your reply deepzero.

Here is a pic of the error messgae i get:

22nb50.png

And thanks for the info regarding FPU.

grizzmo

edit: Thanx, I fished a serial for my name. :D

Edited by grizzmo
Posted

good luck grizzmo :thumbsup:

Posted (edited)

"translated" to "normal" asm:

        MOV EAX,0X7DA
MUL EBX
MOV EBX,6
DIV EBX

dp0 :)

I want to remind you something deepzero.

before you divide eax to ebx ,you must empty EDX

Also

mov ebx,6

cdq ( or xor edx,edx)

div ebx

Thanx for solution

Edited by s3rh47
Posted

good luck grizzmo :thumbsup:

@3rh47,

Thanx for this learning experience.

grizzmo

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