There's no continue directive in VB6.

Is this code below is the best (shortest) solution?

  Dim i As Integer  For i = 1 To 5
	If i = 3 Then
	  GoTo CNT
	End If
	Print i
CNT:
  Next

Edited May 1, 200916 yr by alaphate

Check out this page on MSDN:

http://msdn.microsoft.com/en-us/library/t2at9t47(VS.80).aspx

It explains the following snippet:

Sub exitStatementDemo()
	Dim demoNum As Single
	' Set up an infinite loop.
	Do
		For i As Integer = 1 To 10000000
			demoNum = Int(Rnd() * 100)
			Select Case demoNum
				Case 7 : Exit For
				Case 29 : Exit Do
				Case 54 : Exit Sub
			End Select
		Next i
	Loop
End Sub

Basically you can use "Exit For" to break out of a "For" loop. Im not sure how applicable this is to VB6, as i dont program in either VB6 or VB .NET.

Just installed VB6 to check it out and it had a problem with declaring i as an integer if i left it as part of the For declaration and it wasnt happy with such a large integer, but changing it to:

Sub exitStatementDemo()
	Dim demoNum As Single
	Dim i As Integer	' Set up an infinite loop.
	Do
		For i = 1 To 10000
			demoNum = Int(Rnd() * 100)
			Select Case demoNum
				Case 7 : Exit For
				Case 29 : Exit Do
				Case 54 : Exit Sub
			End Select
		Next i
	Loop
End Sub

Then it compiled fine...

HR,

Ghandi

Edited May 1, 200916 yr by ghandi

Ghandi,

Thanks for the code.

However, Exit For just like c++ break

It break out from the FOR loop

In my sample code, It will print out: 1 2 4 5

and skip 3, so when i=3, it will continue the loop

  Dim i As Integer  For i = 1 To 5
	If not i = 3 Then
		Print i
	End If  Next

It could be done like this also. This just means that the default case isnt 3, so it will execute the code inside the "If not" statement and only jumps over the code when i=3.

HR,

Ghandi

Edited May 1, 200916 yr by ghandi

Ghandi,

Your code is better than mine