try this, it's for beginners, no special knowledge required.

do not patch, make a keygen

cm260807.zip

Edited September 3, 200718 yr by mcpower

try this, it's for beginners, no special knowledge required.

do not patch, make a keygen

Below is a dump with comments of where the license number is processed and then compared to serial number input by the user.

00401077  |> DCC0		   FADD ST,ST							  ;  license number ^ 2
00401079  |. DC05 F0214000  FADD QWORD PTR DS:[4021F0]			  ;  add 753
0040107F  |. DC0D E8214000  FMUL QWORD PTR DS:[4021E8]			  ;  multiply 333
00401085  |. DC25 E0214000  FSUB QWORD PTR DS:[4021E0]			  ;  sub 13
0040108B  |. DC25 D8214000  FSUB QWORD PTR DS:[4021D8]			  ;  sub 15
00401091  |. DC5C24 10	  FCOMP QWORD PTR SS:[ESP+10]			 ;  compare
00401095  |. DFE0		   FSTSW AX
00401097  |. F6C4 44		TEST AH,44
0040109A  |. 7A 12		  JPE SHORT cm260807.004010AE
0040109C  |. 68 98214000	PUSH cm260807.00402198				  ;  ASCII "Absolutely correct...
"
004010A1  |. FFD6		   CALL ESI
004010A3  |. 83C4 04		ADD ESP,4
004010A6  |. 33C0		   XOR EAX,EAX
004010A8  |. 5F			 POP EDI
004010A9  |. 5E			 POP ESI
004010AA  |. 8BE5		   MOV ESP,EBP
004010AC  |. 5D			 POP EBP
004010AD  |. C3			 RETN
004010AE  |> 68 B0214000	PUSH cm260807.004021B0				  ;  ASCII "Wrong answer, have a closer look !

So basicly we want to square the license number, multiply by 333, and subtract 13, then 15.

So keygen;

#include <iostream>
#include <string.h>using namespace std;int main(int argc, char* argv[])
{
	int license;	cout << "KeyGen Solution for 'mcpower's Kegenme 260807'" << endl << "cracked/coded by zart" << endl;
	cout << "Enter a license number: ";	cin >> license;	cout << "Serial number: " << ((((license*2) + 753) * 333) - 13) - 15 << endl;  return 0;

At first you say:

FADD ST,ST ; license number ^ 2

Which is err wrong since '^' means 'power' and not *...

And:

basicly we want to square the license number

You did it correctly in your source though

Might confuse a few people, just wanted to mention it

At first you say:

FADD ST,ST ; license number ^ 2

Which is err wrong since '^' means 'power' and not *...

And:

basicly we want to square the license number

You did it correctly in your source though

Might confuse a few people, just wanted to mention it

I know what I wrote. Short hand math for myself, I use the carrot (^) as a 'raise to the power of'...

number^2 is squared... which is the same thing as number * 2. which is the same thing as number * number, which is the same as pow(num,2)...

Just my math short hand when I'm writing on paper

I still don't get it

Of course '^' means 'raise to the power of' (dunno the exact denotation for it)

-> x ^ 2 == x * x

number^2 is squared... which is the same thing as number * 2

Did I miss something ? x ^ 2 == x * x but x * x != x * 2

That only applies if x is 2

Either you use ^ & * interchangable or I'm too dumb to understand the logic behind your signs...

Square means 'times two' for you ?

Hi.

I'm completely new to this. Could you please tell me which tool you used for opening the file the way you did?

And can you please explain how you were able to extract numbers from this:

00401077  |> DCC0		   FADD ST,ST							 ;  license number ^ 2
00401079  |. DC05 F0214000  FADD QWORD PTR DS:[4021F0]			 ;  add 753
0040107F  |. DC0D E8214000  FMUL QWORD PTR DS:[4021E8]			 ;  multiply 333
00401085  |. DC25 E0214000  FSUB QWORD PTR DS:[4021E0]			 ;  sub 13
0040108B  |. DC25 D8214000  FSUB QWORD PTR DS:[4021D8]			 ;  sub 15

Thank you so much

I still don't get it

Of course '^' means 'raise to the power of' (dunno the exact denotation for it)

-> x ^ 2 == x * x

number^2 is squared... which is the same thing as number * 2

Did I miss something ? x ^ 2 == x * x but x * x != x * 2

That only applies if x is 2

Either you use ^ & * interchangable or I'm too dumb to understand the logic behind your signs...

Square means 'times two' for you ?

Sorry, dumb moment, disregard my "num*2" lol...

The program used was Ollydebug

Got it. Understood the code a little better after watching lena's tut #1. I have now understood why I did what when I wrote a keygen. This was a good exercise, compared to other keygens for noobs I have found up till now. I found one where the key is supposed to be random symbols. I think they were from ASCII >128. That sucked a little. But this one is NICE... Keep up the good work, and thanks for the experience.

i wish if there is a simple tool to make patches and kegen instead of lenthy reverse engineering,

i dont know if there is any software which help you t o build a patch or keygen . very simple just put the name and of the software you want to make a kegen or patch and click on make keygen or make patch and walahaaaaaaaaaaaaa

take care ,

i wish if there is a simple tool to make patches and kegen instead of lenthy reverse engineering,

i dont know if there is any software which help you t o build a patch or keygen . very simple just put the name and of the software you want to make a kegen or patch and click on make keygen or make patch and walahaaaaaaaaaaaaa

take care ,

where would be the fun then??

Stunt.

obviously there wont be any fun but still people are curious.

hello every one.

i am new to the keygenning bit of reversing, so i decided to start east

any way heres my keygen. Please make sure you ONLY enter integer values.

Keygen By Encrypto

is there any ready made patch or crack maker ?

do you mean for this crackme ?

or for general cracking ?

for general cracking dUP is quite useful....

im sure youll be able to find it in the forum somewhere.

is there any ready made patch or crack maker ?

Almost all licenses uses different algros to generate a valid key, therefore you can't really make a general crack/patch maker.

And all coding is different too, unless it's from the same company/an update.

You could make a database that it searches through though, but someone still has to make the patches/cracks, and those databases would be rather large since there are lots of software and different versions of everything.

And all the fun in Reversed engineering would be lost, and you wouldn't learn anything new

Edited November 18, 200717 yr by ante0